Acan of soda is placed inside a cooler. as the soda cools, its temperature t(x)
in degrees celsius is given by the following function, where x
is the number of minutes since the can was placed in the cooler.

t(x)=−12+28e-0.38x

find the initial temperature of the soda and its temperature after 18
minutes.
round your answers to the nearest degree as necessary.

The initial temperature of the soda is 16°C

The temperature of the soda after 18 minutes is -12°C

Step-by-step explanation:

T(x) = -12+28e^-0.38x

When x = 0

T(0) = -12+28e^-0.38(0) = -12+28e^0 = -12+28(1) = -12+28 = 16°C

Initial temperature of the soda is 16°C

When x = 18

T(18) = -12+28e^-0.38(18) = -12+28e^-6.84 = -12+28(0.0011) = -12+0.0308 = -11.9692°C = -12°C (to the nearest degree)

The temperature of the soda after 18 minutes is -12°C

the answer is c just got it on ed

step-by-step explanation:

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)