An article reported the following data on oxygen consumption (ml/kg/min) for a sample of ten firefighters performing a fire-suppression simulation: 28.6 49.4 30.3 28.2 28.9 26.4 33.8 29.9 23.5 30.2compute the following. (round your answers to four decimal places.) a. the sample range ml/kg/minb. the sample variance s2 from the definition (i. e., by first computing deviations, then squaring them, etc.) ml2/kg2/min2c. the sample standard deviation ml/kg/mind. s2 using the shortcut method ml2/kg2/min

a) The sample range 25.9

b) The sample variance is 49.344

c) The sample standard deviation 7.0245                  

Step-by-step explanation:

We are given the following data on oxygen consumption (mL/kg/min):

28.6, 49.4, 30.3, 28.2, 28.9, 26.4, 33.8, 29.9, 23.5, 30.2

a) The sample range

Range = Maximum - Minimum

The sample range 25.9

b) The sample variance

where are data points, is the mean and n is the number of observations.  

Sum of squares of differences =

5.3824 + 341.5104 + 0.3844 + 7.3984 + 4.0804 + 20.4304 + 8.2944 + 1.0404 + 55.0564 + 0.5184 = 444.096

The sample variance is 49.344

c)  The sample standard deviation

It is the square root of sample variance.

The sample standard deviation 7.0245

idk

cfgghbjn bvcdftfghjnbgvfcdrtrfytgyuhuji