Determine the general form of the equation for the circle x^2 + (y + 1)^2 = 2.

x² + y² + 2y - 1 = 0

Step-by-step explanation:

The general form of the equation for the circle:

x² + y² + ax + by + c = 0

Where: a, b and c are constants.

For the given equation:

x² + (y + 1)² = 2

∴ x² + (y + 1) (y+1) = 2

∴ x² + y² + 2y + 1  = 2  ⇒ subtract 2 from both sides

∴ x² + y² + 2y + 1 - 2 = 2 - 2

∴ x² + y² + 2y - 1 = 0

So, the general form of the equation for the circle:

x² + y² + 2y - 1 = 0

add a pic of the graph, then ill edit this "answer" and solve it for you : 3

step-by-step explanation: