Find all numbers such that the square of the number is 48 more than double the number. if you find more than one, then list all the numbers you find in increasing order, separated by commas.?

-6, 8

Step-by-step explanation:

Let the numbers be represented by y

Square of y = y^2

Double y = 2 × y = 2y

Square of the number is 48 more than double the number is written mathematically as

y^2 = 2y +48

y^2 - 2y - 48 = 0

This is a quadratic equation and can be solved by method of factorisation

y^2 -2y - 48 = 0

y^2 + 6y - 8y - 48 = 0

(y^2 + 6y) - (8y - 48) = 0

y(y + 6) - 8(y + 6) = 0

(y + 6)(y - 8) = 0

y = -6, 8

The numbers are -6, 8

b. x + 1

step-by-step explanation:

i'am smart

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!