Write an equation of the line that passed through (7,10) and is perpendicular to the line y=1/2x-9

The perpendicular line passing through the point (7,10) is

2 x+y-24=0

Step-by-step explanation:

Step :1

perpendicular condition :-

The condition of perpendicular lines are

The given line is and given point is (7,10)

the standard form of straight line is y=m x+c

The given line is y= \frac{1}{2}x-9

here m = \frac{1}{2}

now by using perpendicular condition solving the slope of perpendicular line is

straight line equation

Step 2 :-

The equation of the straight line having slope m=-2 and passing through the point (7,10) is

)

There fore the equation of perpendicular straight line is

y-10 = -2 (x-7)

Final answer

The equation of perpendicular straight line is

2 x+y-24=0

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.