Find the value of k so that the point a lies on the line given by equation.

a(2, 2), kx+(k+1)y=2

k = 0

Step-by-step explanation:

Explanation:-

given straight line equation is k x+(k+1)y=2(1)

The point A(2,2) lies on the equation is

substitute x = 2 and y=2

k(2) + (k+1)(2) =2

now simplify 2 k+2 k+2 = 2

subtracting '2' on both sides , we get solution is

4 k +2 -2 = 2-2

4 k =0

k = 0

k = 0

Step-by-step explanation:

kx + (k + 1)y = 2

2k + 2(k + 1) = 2

2k + 2k + 2 = 2

4k + 2 = 2

4k + 2 - 2 = 2 - 2

4k = 0

4k ÷ 4 = 0 ÷ 4

k = 0

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: