In quadrilateral abcd ad=bc, m∠dac=50°, m∠dca=65°, m∠acb=70°. find m∠abc.

m<ABC= 55 degrees

Step-by-step explanation:

m<CAD+m<ACD+m<ADC=180 degrees              Sum of <'s in triangle

50+65+m<CDA=180 degrees                               substitution

m<CDA=65                                                             Algebra

AC=AD=BC                                                             Def of Isos triangle

m<ACB+m< ABC+m<BAC=180 degrees              Sum of <'s in triangle

m<ABC=m<CAB                                                     Def of Isos triangle

70+2m<ABC=180                                                    Substitution    

m<ABC=55                                                              Algebra        

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.