What is the equation of the line that contains point(3, -2) and has a slope of 5?
y = 5x - 17
y = 5x - 13
y = 5x + 13
y = 5x + 17

y = 5x - 17

Step-by-step explanation:

y = mx + c

m = the gradient/slope = 5

y = 5x + c

Substitute (3, -2) into the equation above to find c.

-2 = 5(3) + c

-2 = 15 + c

-2 - 15 = c

-17 = c

y = 5x - 17

Step-by-step explanation:

point(3, -2) and has a slope of 5

Slope m = 5

y1 = -2 and x1 = 3

The equation is

y - y1 = m(x - x1)

y + 2 = 5(x - 3)

y + 2 = 5x - 15

y = 5x - 15 - 2

y = 5x - 17

answer: the common difference is -0.10