What is the equation of the perpendicular line 2x-4y=7 passing through the points (2,-5/4)?

Step-by-step explanation:

We are given;

The equation 2x + 4y = 7

A point (2, -5/4)

We are supposed to determine the equation of a line perpendicular to the given line;

First, we determine the slope of the given line by writing the equation in the form of y= mx + c

2x + 4y = 7

y = -1/2x + 7/4

m₁ = -1/2

But, for perpendicular; m₁×m₂= -1

Therefore;

-1/2 × m₂ = -1

m₂ = 2

Thus, we can get the equation of the line;

Taking another point (x, y)

Thus, the equation of the line in question is

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

the answer is -1 for this question

step-by-step explanation: