Pls me with this question no. 14 asap. will mark brainliest

Work Shown for part (i)

One base of triangle PQR is QR = 4

If the base is QR, then the height is PL = 5, which is perpendicular to QR.

area of triangle PQR = (1/2)*base*height

area of triangle PQR = (1/2)*QR*PL

area of triangle PQR = (1/2)*4*5

area of triangle PQR = 10

Work Shown for part (ii)

Another base for triangle PQR is PR = 8

Imagine rotating triangle PQR so that PR is completely horizontal and flat.

Note: the diagram implies that MR = 8, but instead it's actually PR = 8

For the base PR, the perpendicular height is QM, which we'll label as x for now

area of triangle PQR = (1/2)*base*height

area of triangle PQR = (1/2)*PR*QM

area of triangle PQR = (1/2)*8*x

area of triangle PQR = 4*x

From part (i), we can set 4x equal to 10 since we know the triangle PQR has area 10 square cm.

4x = 10

4x/4 = 10/4

x = 10/4

x = (5*2)/(2*2)

x = 5/2

x = 2.5

the answer is here: : )

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