Arectangular parking lot has a perimeter of 232 feet. the length of the parking lot is 36 feet less than the width. find the length and the width.

The rectangular parking lot has a width of 76 feet and a length of 40 feet

Step-by-step explanation:

Let's find the length and the width of the rectangular parking lot, this way:

Perimeter = 232 feet

Perimeter = 2 Length + 2 Width

Length = Width - 36 feet

Now, substituting, we have:

2 (Width - 36) + 2 Width = 232

2 Width - 72 + 2 Width = 232

4 Width = 232 + 72

4 Width = 304

Width = 304/4 = 76 feet

Length = 76 - 36 = 40 feet

The rectangular parking lot has a width of 76 feet and a length of 40 feet

a) 32pie square meters

step-by-step explanation:

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi