Sureepan borrows 40 000 bhat to buy a new computer. the bank charges 7.5% interest compounded yearly. sureepan agrees to pay a half of the amount still owing at the end of each year after the interest has been compounded. determine how much sureepan would have paid back at the end of 4 years.

Explanation:

year 1 (all the values are is $)                                                  

        (including the interest)                     40,000 + 3,000 = 43,000

       (half of the debt)                               43,000 / 2 = 21,500

year 2 (all the values are is $)                                                  

        (including the interest)                     21,500 + 1612.50 = 23,112.50

       (half of the debt)                               23,112.50 / 2 = 11,556.25

year 3 (all the values are is $)                                                  

        (including the interest)                     11,556.25 + 866.72 = 12,422.97

       (half of the debt)                               12,422.97 / 2 = 6,211.48

year 4 (all the values are is $)                                                  

        (including the interest)                     6,211.48 + 465.86 = 6,667.35

       (half of the debt)                               6,667.35 / 2 = 3,338.67                        

Amount paid back at the end of 4 years ($) :

a ruler? idk

step-by-step explanation:

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d