Asequence is defined recursively using the formula f(n + 1) = f(n) – 5 . which sequence could be generated using this formula?

*1, –5, 25, –125,
*2, 10, 50, 250,
*3, –2, –7, –12,
*4, 9, 14, 19,

Option C. 3, -2, -7, -12

Step-by-step explanation:

The sequence is defined recursively using the formula f(n+1) = f(n) - 5

We have to identify the sequence generated by this formula.

B). 1, -5, 25, -125

f(n+1) = -5 and f(n) = 1

Therefore - 5 = 1 - 5

⇒ -5 ≠ -4

This sequence is not following the formula.

B). 2, 10, 50, 250

f(n+1) = 10 and f(n) = 2

Now we use the formula

10 = 2 - 5

10 ≠ -3

This sequence is not following the formula.

C). 3, -2, -7, -12

f(n+1) = -2 and f(n) = 3

We put this value in the formula

-2 = 3 - 5

-2 = -2

Therefore , the sequence is following the formula.

D). 4, 9, 14, 19

f(n+1) = 9 and f(n) = 4

9 = 4 - 5

9 ≠ -1

Therefore the formula is not applicable to form this sequence.

Option C. is the answer.

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong