Arectangle has a perimeter of 50 m and a side length of l.

a. express the other dimension of the rectangle in terms of l.

The other dimension can be expressed as

(50 - 2L)/2

Step-by-step explanation: First and foremost, we would let the other dimension be represented by B. Then, the perimeter of a rectangle is measured as L+L+B+B or better put;

Perimeter = 2L + 2B

Where L is the measurement of the longer side and B is the measurement of the shorter side.

In this case the perimeter of the rectangle measures 50m, and this can now be written as

50 = 2L + 2B

Subtract 2L from both sides of the equation

50 - 2L = 2L - 2L + 2B

50 -2L = 2B

Divide both sides of the equation by 2

(50 - 2L)/2 = B

  25-L

Step-by-step explanation:

Let W represent the other side length. The perimeter (P) of the rectangle is ...

  P = 2(W+L)

Solving for W, we get ...

  P/2 = W+L

  P/2 -L = W

Filling in the given value for P, we find ...

  W = 50/2 -L = 25 -L

The other dimension is (25-L) meters.

the answer is a

step-by-step explanation:

true

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