The length of a rectangle is 12 centimeters less than its width . what are the dimensions of the rectangle if it’s area is 108 square centimeters?

Length = 6 and Width = 18 = 6(18) = 108

Step-by-step explanation:

Length = W-12

Areas of a rectangle = L(W)

= W-12(W) = 108

W^2-12w = 108

W^2-12w-108=0

Solve for W

(W-18) (W+6)

W = 18, -6

L = 18-12 = 6

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752