Two cyclists leave city at same time, one going east and the other going west. the westbound cyclist bikes 3 mph faster than the eastbound cyclist. if after 6 hours they are 162 miles apart, how fast is each cyclist riding?

Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.

Solution:

Let us assume that x is speed of slower eastbound cyclist

So, x+3 will be the speed of faster westbound cyclist

We know that distance is the product of speed and time. That is,

West-bound DATA:

Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles

East-bound DATA:

Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles

On solving,

Distance apart = 162

So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.