If angle a is congruent to itself by the reflexive property, which transformation could be used to prove δabc ~ δade by aa similarity postulate?

triangles abc and ade, in which point b is between points a and d and point c is between points a and e

translate triangle abc so that point b lies on point e to confirm ∠b ≅ ∠e.
translate triangle abc so that point c lies on point e to confirm ∠c ≅ ∠e.
dilate δabc from point a by the ratio segment ad over segment ab to confirm segment ad ~ segment ab.
dilate δabc from point a by the ratio segment ae over segment ac to confirm segment ae ~ segment ac.

its definatley   this on your answer choice?

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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