Mathematics, 27.01.2020 22:31 yuluvk

What are the solutions of 3 x^2-x+4=0

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Answer from: justhereforanswers13

The solution of given equation for x is (0.16 + i 1.14) , (0.16 - i 1.14)

Step-by-step explanation:

Given as :

The quadratic equation is as 3 x² - x + 4 = 0

Since The given equation is quadratic

∵, Standard quadratic equation is ax² + bx + c = 0

Now, x = $\frac{-b\pm \sqrt{b^{2} - 4\times a\times c}}{2\times a}$

Comparing the equation

i.e x = $\frac{-(-1)\pm \sqrt{(-1)^{2} - 4\times 3\times 4}}{2\times 3}$

or, x = $\dfrac{1\pm \sqrt{(1-48)}}{6}$

Or, x = $\dfrac{1\pm \sqrt{(-47)}}{6}$

Or, x = $\dfrac{1\pm i6.85}{6}$

Or, x = (0.16 + i 1.14) , (0.16 - i 1.14)

So, The solution of given equation for x = (0.16 + i 1.14) , (0.16 - i 1.14)

Hence, The solution of given equation for x is (0.16 + i 1.14) , (0.16 - i 1.14) . Answer

Answer from: Quest

$x=2\sqrt{10}$

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

$6^2+2^2=x^2$

simplifying:

$6^2+2^2=x^2\\36+4=x^2\\40=x^2\\x=\sqrt{40}$

to further simplify this radical, we need to use the property $\sqrt{x*y}=\sqrt{x} \sqrt{y}$

thus

$x=\sqrt{40}\\ x=\sqrt{4}\sqrt{10} \\ x=2\sqrt{10}$

What is the value of x? leave your answer in simplest radical form.

Answer from: Quest

explanation:

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