Surveys indicate that 5% of the students who took the sats had enrolled in an sat prep course. 30% of the sat prep students were admitted to their first choice college, as were 20% of the other students. you overhear a high school student say he got into the college he wanted. what is the probability he didn't take an sat prep course?

The required probability is 0.927

Step-by-step explanation:

Consider the provided information.

Surveys indicate that 5% of the students who took the SATs had enrolled in an SAT prep course.

That means 95% of students didn't enrolled in SAT prep course.

Let P(SAT) represents the enrolled in SAT prep course.

P(SAT)=0.05 and P(not SAT) = 0.95

30% of the SAT prep students were admitted to their first choice college, as were 20% of the other students.

P(F) represents the first choice college.

The probability he didn't take an SAT prep course is:

Substitute the respective values.

Hence, the required probability is 0.927

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

cut 138 centimeters off

step-by-step explanation:

250-112 = 138