Write the slope intercept form of the equation of the line with a slope of -2/5 that passes through 15, -9/2

The equation of line in slop-intercept form  is y = +

Step-by-step explanation:

Given as :

The slope of the a line = m =

The line is passes through points = 15 ,

According to question

Equation of line in slope - intercept form

y - = m × ( x - )

Or, y - ( ) =   × ( x - 15 )

Or, y  - ( ) =   ×  x  - ( ) × 15

Or, y  - ( ) =   ×  x  + 6

Or, y =   ×  x  + 6 -

Or, y =   ×  x  +

Or, y = ×  x +

So, The equation of line in slop-intercept form  y = ×  x +

Hence, The equation of line in slop-intercept form  is y = +  Answer

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)