How to solve a classmate draws a parallelogramfor whichone side is twice as long as the other. if one side is 26 units, what are all the possible lengths of the perimeter?

length when perimeter is 78 units: a=26 ,b=13

Length when perimeter is 156 units:

a=26 , b=52

Step-by-step explanation: Given one side =26 , the other is twice as long

Perimeter of a parallelogram =2(a+b)

Using perimeter=78= 2(26+b)

78=52+2b

78-52=2b

26=2b

b=26/2

b=13

When perimeter is 78 units a=26,b=13

Using perimeter =156 units

156=2(26+b)

156=52+2b

156-52=2b

104=2b

b=104/2

b=52

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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