Asquare that is 5yd on a side is placed inside a rectangle that has a width of 11yd and a length of 17 yd. what is the area of the region inside the rectangle that surrounds the square?

162  sq. yds.

Step-by-step explanation:

Given : A square that is 5yd on a side is placed inside a rectangle that has a width of 11yd and a length of 17 yd.

Then , Area of rectangle = length x width

= 11 yd  x 17 yd = 187 sq. yds.

Area of square = (side)²  

= (5 yd)² = 25  sq. yds.

Now , the area of the region inside the rectangle that surrounds the square will be Area of rectangle - Area of square

= 187 sq. yds.- 25  sq. yds.

=162  sq. yds.

Hence, the area of the region inside the rectangle that surrounds the square is 162  sq. yds. .

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