When 258 college students are randomly selected and surveyed, it is found that 106 own a car. find a 99% confidence interval for the true proportion of all college students who own a car. 0.351 < p < 0.471 0.332 < p < 0.490 0.339 < p < 0.482 0.360 < p < 0.461

0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

, where n= sample size

= sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car =

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the  99% confidence interval for the true proportion(p) of all college students who own a car will be :

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

justin bieber ml.