Aphoto that is 4 in. wide and 6 in. high is enlarged to a
poster that is 3 ft wide and 4 ft high. what is the ratio
of the width of the photo to the width of the poster?

The ratio of the width of the photo to the width of the poster is 1:9 or 1/9

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Photo =  4 in. wide and 6 in. high

Poster = 3 ft wide and 4 ft high

2. What is the ratio  of the width of the photo to the width of the poster?

Let's recall that 1 foot = 12 inches

Let's convert the width of the poster to inches, this way:

3 feet = 3 * 12 inches

3 feet = 36 inches

The width of the poster is 36 inches

Now, we calculate the radio, as follows:

Ratio = Width of the photo in inches/Width of the poster in inches

Ratio = 4/36 = 1/9 (Simplifying)

The ratio of the width of the photo to the width of the poster is 1:9 or 1/9

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet