1. factor:
-x^10–4x^15–3x^20

2. factor:
6x^2–4x^3+10x^4

3. factor:
–3m^2–6m^3+12m^5

could someone me with this? you! > ﹏

Basically find the GCF for each integer and then just multiply to equal to the original integer
1. -x^10(1 + 4x^5 + 3x^10)
2. 2x^2(3 - 2x + 5x^2)
3. 3m^2(-1 - 2m + 4m^3)

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.

Depends by how many apples are in a case