What quantity of 78% chlorine solution must be mixed with a 23% chlorine solution to produce 477.16 ml of 60% solution?

321 mL of 78% chlorine solution must be mixed with 156.16 mL of 23% chlorine solution

Step-by-step explanation:

Let

x ----> quantity of 78% chlorine solution in milliliters

y ----> quantity of 23% chlorine solution in milliliters

we know that

The quantity x of 78% chlorine solution mixed with a quantity y of 23% chlorine solution produce 477.16 mL of 60% solution

so

----> equation A

----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (321, 156.16)

therefore

321 mL of 78% chlorine solution must be mixed with 156.16 mL of 23% chlorine solution

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step-by-step explanation: