The altitude of the triangle abc, segment da, has been
drawn. derive a formula for the area of triangle bca that
depends on the measure of angle b along with side
lengths a and c

sin(B)= h/c

h= csin(b)

Area= 1/2acsin(B)

Step-by-step explanation: i got the answers frfr on edge smh yall know how that is

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2