1. solve the system by substitution . 2x+y=-11 . 3x-4y=11 . a. (3,5) . b. (-5,-3) . c. (-3,-5) . d. (5,3).

In the first equation, moving 2x over gives "y = -2x-11". Placing this into the second equation gives "3x - 4(-2x-11) = 11", or "3x+8x+44 = 11", which can be reduced to "11x= -33" or "x = -3". Replacing the "x" with -3 in the first equation gives "-6 + y = -11" or "y = -5". This gives a solution of (-3, -5), or answer C.

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