An angle whose measure is –102° is in standard position. in which quadrant does the terminal side of the angle fall? quadrant i quadrant ii quadrant iii quadrant iv

it will be the third quadrent

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66answer:

step-by-step explanation:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!