Amoving company charges a flat rate of $75 plus and additional $0.19 per mile driven. which inequality correctly represents how far the company must drive to earn at least $100? round to the nearest mile.

For this case, the first thing we must do is define a variable.

We have then:

x: number of miles.

By the time the company earns at least $ 100 we have the following inequality:

From here, we clear the value of x.

We have then:

the company must drive to earn at least $ 100 more than or equal to 132 miles

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;