At most, alana can spend $40 on carnival tickets. ride tickets cost $4 each, and food tickets cost $2 each. alana buys at least 16 tickets. the system of inequalities represents the number of ride tickets, r, and the number of food tickets, f, she buys.
r + f ≥ 16
4r + 2f ≤ 40
what is the maximum number of ride tickets she can buy?
4
6
10
12

We can let r be the number of food tickets and f be the number of food tickets. Since Alana can spend at most $40, that means the total of price bought for r and f must be less than or equal to $40. In addition, since Alana buys at least 16 tickets, this also means that the total of r and f is 16. Mathematically, we have these inequalities: (1) 4r + 2f ≤ 40 and (2) r + f ≥ 16 Multiplying -2 in (2), we have 4r + 2f ≤ 40 -2r - 2f ≤ 32 Adding both inequalities, 2r ≤ 8 r ≤ 4 Since r must be less than or equal to 4.Thus the answer is A.

X> -2 is the simplified version.