Scores for a common standardized college aptitude test are normally distributed with a mean of 512 and a standard deviation of 106. randomly selected men are given a test preparation course before taking this test. assume, for sake of argument, that the test has no effect

if 1 of the men is randomly selected, find the probability that his score is at least 559.5.
p(x > 559.5) =

if 18 of the men are randomly selected, find the probability that their mean score is at least 559.5.
p(m > 559.5) =

Let x denotes the score of a man.

As per given , we have

If 1 of the men is randomly selected, find the probability that his score is at least 559.5 will be :-

Hence, the probability that his score is at least 559.5 is 0.3271 .

Let M be the sample mean.

Hence, if 18 of the men are randomly selected, find the probability that their mean score is at least 559.5 is 0.0287.

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²