Find the x intercept of the parabola with vertex (1,20) and u intercept (0,16). write answer in form (x1,y2)(x2,y2)

Hello,

Answer (1-√5,0) , (1+√5,0)

Indeed,

S=(1,20)
==> y=k*(x-1)²+20
(0,16) is a point of the parabola
==>16=k*(0-1)²+20==>k=-4
Parabola: y=-4(x-1)²+20
if y=0 then -4(x-1)²+20=0==> 4(x-1)²=20=> (x-1)²=5 ==> x=1+√5 or x=1-√5

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