An acute, isosceles triangle has a vertex angle measuring 78 degrees. what are the measures of the other two angles?

Step-by-step explanation:

180-78=102

102/2=51

the other 2 angles are 51 degrees

Step-by-step explanation: since it is an isoceles triangle two sides are equal thus 2 angles are equal.

Therefore, let's take the two angles as x

78+ x+x = 180 ( angle sum property)

Thus , 2x= 180-78

X = 102/2

X= 51 degrees

Hope I helped you !!

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?