Can someone help me with c. on #8 so i can know

(0, - 1), (- 4, 3 ) and (0, 7 )

Step-by-step explanation:

Substitute the coordinates of the points given into the left side of the equation and if equal to the right side then they lie on the circle

Given equation

x² + (y - 3)² = 16

(0, - 1)

0² + (- 1 - 3)² = (- 4)² = 16 ← lies on circle

(0, 1 )

0² + (1 - 3)² = (- 2)² = 4 ≠ 16 ← not on circle

(- 4, 3)

(- 4)² + (3 - 3)² = 16 + 0 = 16 ← lies on circle

(0, 7 )

0² + (7 - 3)² = 4² = 16 ← lies on circle

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)