What is the perimeter, P, of a rectangle that has a length of x + 6 and a width of y - 1?
P = x + y + 5
P = x + y - 7
P = 2x + 2y + 10
P=2x + 2y - 10

P = 2x + 2y + 10

Step-by-step explanation: The perimeter (P) of a rectangle is given as

P = 2L + 2W

By factorizing the right hand side of the equation we now have

P = 2(L + W)

However, the length of the rectangle is given as x + 6 and the width is given as y - 1

If P = 2(L + W), then

P = 2(x + 6 + {y - 1} )

P = 2(x + 6 + y -1)

P = 2(x + y + 5)

After expanding the bracket, we now have

P = 2x + 2y + 10

the answer is simply just 6n add the two together as they have an n