In triangle ABC, the measure of angle B is 44 degrees more than three times the measure of angle A. The measure of angle C is 61 degrees more than the measure of angle A. Find the measure of each angle

m∠A = 15°; m∠B = 89°; m∠C = 76°

Step-by-step explanation:

The sum of the three interior angles of a triangle is 180°.

             Let x = m∠A

Then 3x + 44 = m∠B

    and x + 61 = m∠C

x + 3x + 44 + x + 61 = 180

                  5x + 105 = 180

                            5x =   75

                               x =   15

m∠A =                                       15°

m∠B = 3(15) + 44 = 45 + 44 =   89°

m∠C =                       15 + 61 =  76°

                                      Sum = 180°

the answer for this question is 38