A playground at a mall is in the shape of a rectangle, and there is a 144 foot long fence around it. If the
rectangle is 6 feet longer than it is wide, what is the width, in feet, of the rectangle?

Width of the playground is 33 foot.

Explanation:

A fence around the playground represents the perimeter.

If the playground is rectangular in shape, then the perimeter of the rectangle is known.

Perimeter of the rectangle = 144 foot

Let, width = b foot

Given:

length (l) = b+6 foot

We know,

Perimeter of the rectangle = 2 (l + b)

Putting the values of l and b in above equation we get,

length (l) = 33 + 6 foot

l = 39 foot

Hence, width of the playground is 33 foot.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

i dont know nkw

step-by-step explanation:

kenffledkedncklzkdfeserw