For the points Upper P 1 (negative 3 comma 1 comma 5 )and Upper P 2 (1 comma 5 comma 0 ), find the direction of ModifyingAbove Upper P 1 Upper P 2 with right arrow and the midpoint of line segment Upper P 1 Upper P 2.

The direction of is (4,4,-5).

The midpoint of the line segment is in (-1 , 3 , 2.5)

Step-by-step explanation:

The direction of a vector that goes from the initial point A to the final point B can be calculated as the subtraction of B with A. In this case:

The midpoint of the line segment between two points A and B can be obtained as the halving of the addition of the vector A with the vector B. The line segment AB and the vector A+B make a rhombus. These lines will cross each other in their respective mediatrix. Therefore, if you obtain the point of the mediatrix of the vector A+B, you will find the midpoint of the segment AB. In this case:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3