A special deck of cards has 5 red cards, and 4 purple cards. The red cards are numbered 1, 2, 3, 4, and 5. The purple cards are numbered 1, 2, 3, and 4. The cards are well shuffled and you randomly draw one card. R = card drawn is red E = card drawn is even-numbered a. How many elements are there in the sample space? b. P(E) = Round your answer to two decimal places.

a. 9

b. 4/9 or 0.444

Step-by-step explanation:

R=red card={R1,R2,R3,R4,R5}

E=even card={R2,R4,P2,P4}

n(R)=5

n(E)=4

a.

There 5 red and 4 purple card so, the sample space would be

Sample space=S={R1,R2,R3,R4,R5,P1,P2,P3,P4}

number of elements in sample space=n(S)=9

So, the number of elements in the sample space are 9.

b.

P(E)=n(E)/n(S)

P(E)=4/9 or 0.444

Thus, the probability of an even numbered card is 0.444.

answer: idk

step-by-step explanation: