A delivery of 50 transistors contains 40 good ones and 10 defectives. In a test five of them are checked. How many possibilities are there to have 3 good ones and 2 defective transistors in the test set?

0.2048

Step-by-step explanation:

p(good transistor) = 40/50 = 4/5

p(defective transistor) = 10/50 = 1/5

the probability of having 3 good ones and 2 defective transistors in the test set :

= 5C3×(4÷5)³×(1÷5)²

= 0.2048

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

step-by-step explanation:

sry but any answer choices