Use the four-step procedure to solve the following problem. A mixture of 30 lbs. of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates worth 90¢ a pound. How many pounds of each kind were used to make the mixture?

10lbs of the $1.5 a pound chocolate was used in the mixture.

20lbs of the 90¢ a pound chocolate was used in the mixture.

Step-by-step explanation:

Let x represent the number of pounds of the $1.5 a pound chocolate that was used in the mixture.

Let x represent the number of pounds of the 90¢ a pound chocolate that was used in the mixture.

The total number of pounds in the mixture is 30. It means that

x + y = 30

A mixture of 30 lbs. of candy sells for $1.10 a pound. This means that the total cost of 30lbs of the mixture is

30 × 1.1 = $33

This means that

1.5x + 0.9y = 33- - - - - - - - -- - 1

Substituting x = 30 - y into equation 1, it becomes

1.5(30 - y) + 0.9y = 33

45 - 1.5y + 0.9y = 33

- 1.5y + 0.9y = 33 - 45

- 0.6y = - 12

y = - 12/ - 0.6

y = 20

x = 30 - y = 30 - 20

x = 10

5x+2x=49

7x=49

x=7. 35 apples