Find the angle of intersection of the plane −3x−5y+3z=3−3x−5y+3z=3 with the plane −5x+3y−5z=−4−5x+3y−5z=−4. Answer in radians: and in degrees:

has normal vector (-3, -5, 3)

has normal vector (-5, 3, -5)

Compute the angle between these normal vectors:

the answer is c

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