A 100-watt (W) light bulb has resistance R = 144 ohms (Ω) when attached to household current, where the voltage varies as V = V0 sin(2πft) (V0 = 110 V, f = 60 Hz). The energy (in joules, J) expended by the bulb over a period of T seconds isU =

P(t)dt

where P = V 2/R (J/s) is the power. Compute U if the bulb remains on for 5 h.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

if x = 1, then the answer is 3.5

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: