Solve the equation in the interval from \dfrac{3\pi}{2} 2 3π start fraction, 3, pi, divided by, 2, end fraction too \dfrac{9\pi}{2} 2 9π start fraction, 9, pi, divided by, 2, end fraction. Your answer should be in radians. All choices are rounded to the nearest hundredth. \sin(x)=0.65sin(x)=0.65.

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Step-by-step explanation:

We have been given an equation . We are asked to solve the given equation in the interval .

Taking inverse of sine function, we will get:

General solutions of the equation would be:

Now, we need to find value of x such that:

When

When :

We can see that is greater than , therefore, the solutions for the given equation are .