Mathematics, 11.02.2020 20:39 mikewalton566

This data is from a sample. Calculate the mean, standard deviation, and variance. Suggestion: use technology. Round answers to two decimal places. x 10.1 45.6 18.9 17.9 18.1 15.7 26.7 36.9

Mean =

Standard Deviation =

Variance =

Ooops - now you discover that the data was actually from a population! So now you must give the population standard deviation.

Population Standard Deviation =

Answers: 3

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Answer from: zibnmustafah

Mean = 189.9

Standard Deviation = 31697.093

Variance = 178.037

Population Standard Deviation = 166.538 .

Step-by-step explanation:

We are given the following data below;

X X - X bar $(X - Xbar)^{2}$

10.1 10.1 - 189.9 = -179.8 32328.04

45.6 45.6 - 189.9 = -144.3 20822.49

18.9 18.9 - 189.9 = -171 29241

17.9 17.9 - 189.9 = -172 29584

18.1 18.1 - 189.9 = -171.8 29515.24

15.7 15.7 - 189.9 = -174.2 30345.64

26.7 26.7 - 189.9 = -163.2 26634.24

36.9 36.9 - 189.9 = -153 23409

$\sum (X-Xbar)^{2}$ = 221879.65

Mean, X bar = $\frac{\sum X}{n}$ = $\frac{10.1 +45.6+ 18.9+ 17.9+ 18.1+ 15.7+ 26.7+ 36.9}{8}$

= 189.9

Variance = $\frac{\sum (X - Xbar)^{2} }{n-1}$ = $\frac{221879.65}{8-1}$ = 31697.093

Standard deviation = $\sqrt{\frac{\sum (X - Xbar)^{2} }{n-1}}$ = $\sqrt{31697.093}$ = 178.037

Now we find that the data was actually from a population so now the formula for Population Standard deviation is given by = $\sqrt{\frac{\sum (X - Xbar)^{2} }{n}}$

Population Standard Deviation = $\sqrt{\frac{221879.65 }{8}}$ = 166.538 .

Answer from: Quest

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.

Answer from: Quest

Istg idk..if there all the same length there all the same number but use google
How do you find the area of similar figures given a side length?

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