What is an equation of the line that had slope -4 and passes through the point (-2, -5)?

y  =  −4x  −  13

MARK ME BRAINLIEST

Slope-intercept form:  y = mx + b

[m is the slope, b is the y-intercept or the y value when x = 0 ---> (0, y) or the point where the line crosses through the y-axis]

Since you know m = -4, plug it into the equation

y = mx + b

y = -4x + b    To find b, plug in the point (-2, -5) into the equation

-5 = -4(-2) + b    [two negative signs cancel each other out and become positive]

-5 = 8 + b     Subtract 8 on both sides to get "b" by itself

-13 = b

y = -4x - 13

(-1,-0.5)

step-by-step explanation:

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8