The school that Jennifer goes to is selling tickets to a play. On the first day of ticket sales the
school sold 3 adult tickets and 12 child tickets for a total of $141. The school took in $197 on the
second day by selling 13 adult tickets and 6 child tickets. What is the price each of one adult
ticket and one child ticket?

Adult ticket = $11

Children ticket = $9

Step-by-step explanation:

Let the price of adult tickets be x and let the price of children's ticket be y

For the first day, the equation of sales can be put as

3x + 12y = 1411

For the second day, the equation of sales can be put as:

13x + 6y = 1972

We then take these two equations together and solve simultaneously.

3x + 12y = 1411

13x + 6y = 1972

Solving by elimination method, we Multiply through equation 1 by 13 and multiply through equation 2 by 3.

39x + 156y = 18333

39x + 18y = 5914

Then subtract equation 4 from equation 3

138y =1242

y = 9

Substitute "y=9" into equation 1 to find x

3x + 12(9) =141

3x + 108 = 141

3x = 141 - 108

3x = 33

x = 11

Hence,

Price of adult ticket = $11

Price of children ticket = $9

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

the thermometer is precise but not accurate

step-by-step explanation: