The length of a rectangle is three times it's width. If the width is diminished by 1 m and length is increased by 3 m, the area of the rectangle that is formed is 72 m². Find the dimensions of the original rectangle.

the length is 15 m and the width is 5 m

Step-by-step explanation:

Let L represent the original length of the rectangle.

Let W represent the original width of the rectangle.

The length of a rectangle is three times it's width. This means that

L = 3W

If the width is diminished by 1 m and length is increased by 3 m, the area of the rectangle that is formed is 72 m². This means that

(L + 3)(W - 1) = 72

LW - L + 3W - 3 - 72 = 72 + 3

LW - L + 3W = 75 - - - - -- - - - - - 1

Substituting L = 3W into equation 1, it becomes

3W × W - 3W + 3W = 75

3W² = 75

W² = 75/3 = 25

W = √25 = ±5

The width cannot be negative. Therefore, the width is 5 m

L = 3W = 3 × 5 = 15 m

2x3 – 6x2 – 14x + 24 square centimeters

if i'm wrong i'm sorry : )

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐