Distance from Palo Alto to Beijing. The surface of the earth is reasonably approximated as a sphere with radius R = 6367.5km. A location on the earth’s surface is traditionally given by its latitude θ and its longitude λ, which correspond to angular distance from the equator and prime meridian, respectively. The 3-D coordinates of the location are given by

The 3-D coordinates of the location of a point on the earth's surface is given by (R₀ₐ ×cosλ ×cosθ,  R₀ₐ×sinλ×cosθ,  R₀ₐ×sinλ)  where λ =longitude and θ  = latitude

and the distance between points on the surface such as two cities  is given by P₁ = (x₁, y₁, z₁) and P₂ = (x₂, y₂, z₂) = |P₁ P₂| = √((x₂-x₁)² + (y₂-y₁)² + (z₂ - z₁)²)

Step-by-step explanation:

If the center of the earth is marked O the location of a point is given in longitude and latitude as λ   and  θ respectively then  where normally we have

-180 ° ≤ λ ≤ 180 ° and 90 ° ≤ θ ≤ 90°

However in cartesan coordinates, considering the radius of the earth and specifying the location of a point on the surface of the earth in three dimensions of the x, y and z coordinates with distance from the earth center = R where R = |Oa| = 6367.5km and  the center of the Earth is O,   then a point, a  on the surface of the earth has   the x, y and z Cartesian coordinates we have

a = (xₐ, yₐ, zₐ) = (R×cosλ×cosθ, R×sinλ×cosθ, R×sinλ)

Hence the 3-D coordinates of a location is given by

(R₀ₐ ×cosλ ×cosθ,  R₀ₐ×sinλ×cosθ,  R₀ₐ×sinλ) with R₀ₐ = the distance of the point a to the center of the earth

Distance between two points is given by P₁ = (x₁, y₁, z₁) and P₂ = (x₂, y₂, z₂) = |P₁ P₂| = √((x₂-x₁)² + (y₂-y₁)² + (z₂ - z₁)²)

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

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step-by-step explanation: